No. A 128k requires 16 working RAM chips too. It's this simple: The Motorola 68000-based Macintoshes are 16 bit computers with 16 bit data busses and 16 bit wide RAM. Each chip of the type installed in these machines is *one bit wide*, which means you need sixteen of them in parallel to give you your full 16 bit memory. Three missing chips means you have a memory bank with only 13 functional bits, and that just isn't going to work regardless of how "deep" the bank is.