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8100/80AV Unstable

The jumpers represent different powers of 2 and they're additive. Hence, 0 => 2^0 =1; 1 => 2^1 = 2; 2 => 2^2 = 4.

For example, jumpers on 0 and 2 gives you 1 + 4 = 5, so SCSI ID 5.

Jumpers on 0, 1 and 2 would give you 1 + 2 + 4 = 7.

Some devices actually label the jumpers 1, 2, and 4, instead of 0, 1, and 2, which is a little easier to understand.
Ah that makes sense. I've only ever seen ones where they label them 1, 2, and 4
 
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