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Juicy Crumb G4 Pro Speaker USB Help

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Huzzah! Salvation for the G4 Pro speakers!

I need help finding the correct USB power supply of 12V 20W via USB-C. I'm finding endless 12V automotive outlet adapter but not as much luck with AC.

Does anyone have a USB-C suggestion?
 
you can find some USB-C power adapters that can negotiate up to 20V 100W on amazon
I've come across a few of those. In my effort not to use Amazon, I've not searched it but I suppose it does have its uses. Feels like a job for RadioShack : )

Am I correct in assuming that a 20V 24W adapter will only provide the 20W that the speaker adapter is looking for? Or do I need exactly 20W?

mac27 - I was very happy to see this. I use my acrylic Cinema HD monitor with my IntelBook and the G4 speakers are, well, a perfect match. I'll let you know how it goes.
 
Generally what voltages PD chargers will supply is written on the charger itself.

If you have any USB PD chargers in the house already, might be worth squinting at their fine print to see if they can do it.

12V isn't an uncommon voltage though, I think...
 
Am I correct in assuming that a 20V 24W adapter will only provide the 20W that the speaker adapter is looking for? Or do I need exactly 20W?

I find it's best to think about wattage/current as a maximum rating, or as a capacity.

A 20V 24W adapter means that it can provide a maximum of 24W of power, or 1.2A. The speakers will only pull as much current as required, in this case up to 20W. The adapter won't force extra current onto the speakers.

It's like a data transfer speed, plugging a device into a USB 2.0 port won't force all transfers at 480 mbps, that's just the maximum it can provide.
 
The adapter controls the voltage.

The load (speaker) controls the current.

The load could try to take more current than the adapter allows so it's important that the adapter is chosen to handle whatever current is required.

A fuse can be used to protect the adapter if the load tries to take too much current.

A load is a resistance.

power = voltage x current
voltage = current x resistance
current = voltage ÷ resistance
A short circuit is a divide by zero error.
 
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